Peak Wattage vs. RMS
#1
Three Wheelin'
Thread Starter
Peak Wattage vs. RMS
I forget what the conversion is for Peak vs RMS Power. My Speakers are the MB Quart Q Series Components. Handling Power of 90-170 Watts. What is the power I would need to handle these in RMS Wattage.
Thanks
Thanks
#2
NJ_CLS_driver:
Peak is just RMS*sqrrt(2)...so you would divide peak by the square root of 2, ~.707, to get RMS. But a lot of speaker manufacturers don't go by this rule...a lot of the RMS and peak values are quite arbitrary...but that's the actual conversion.
Austin519
Peak is just RMS*sqrrt(2)...so you would divide peak by the square root of 2, ~.707, to get RMS. But a lot of speaker manufacturers don't go by this rule...a lot of the RMS and peak values are quite arbitrary...but that's the actual conversion.
Austin519
#3
Three Wheelin'
Thread Starter
Austin, thanks. The reason I was asking, was that I bought the MB Quart QM218.61 Q Series Compontents for the front, and they are rated as 90-170 Watts. No RMS
#5
Hey Austin519: Isn't the conversion multiply instead of divide? Because RMS is always lower than peak. And by dividing it, then the RMS would be greater than peak, which it really isn't.
#7
Originally posted by Austin519
chizad1980:
Nope. The sqrrt(2) is 1.41. So Peak/sqrrt(2) = Peak*.707 = RMS, as I said. The sqrrt(2) > 1.
Austin519
chizad1980:
Nope. The sqrrt(2) is 1.41. So Peak/sqrrt(2) = Peak*.707 = RMS, as I said. The sqrrt(2) > 1.
Austin519
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#8
chizad1980:
My entire statement was correct. The statement I just made that you're agreeing with is the exact same statement as I said first. I believe you just read it incorrectly.
Austin519
My entire statement was correct. The statement I just made that you're agreeing with is the exact same statement as I said first. I believe you just read it incorrectly.
Austin519
#10
chizad1980:
"Peak is just RMS*sqrrt(2)...so you would (1)divide peak by the square root of 2,(2) ~.707, to get RMS."
(1) = divide by the square root of 2 = 1/sqrrt(2) ~ .707 = (2)
Now please stop wasting my time by having me come back to this post thinking that someone asked a Q when it's just you being annoying...
Austin519
"Peak is just RMS*sqrrt(2)...so you would (1)divide peak by the square root of 2,(2) ~.707, to get RMS."
(1) = divide by the square root of 2 = 1/sqrrt(2) ~ .707 = (2)
Now please stop wasting my time by having me come back to this post thinking that someone asked a Q when it's just you being annoying...
Austin519
#11
I know what RMS is! I was just saying that your very first statement was partially incorrect. I am talking about this: 2,(2) ~.707 The ~ means "about" right. Well, what does the other stuff you posted refer to? Because dividing peak by the square root of 2 is correct, you say that, but you also say it is ~.707, which it is not!
#14
chizad1980:
"Well, what does the other stuff you posted refer to? Because dividing peak by the square root of 2 is correct, you say that, but you also say it is ~.707, which it is not!"
1/sqrrt(2) ~.707
I've removed my subscription to this thread...so if that didn't clear up what you miscontrued I guess it's a lost cause.
Austin519
"Well, what does the other stuff you posted refer to? Because dividing peak by the square root of 2 is correct, you say that, but you also say it is ~.707, which it is not!"
1/sqrrt(2) ~.707
I've removed my subscription to this thread...so if that didn't clear up what you miscontrued I guess it's a lost cause.
Austin519
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