I would like to know how many car lengths ~ in a quarter mile race from a 14.8 sec. car like the 04' tl and a M3 which is like low to mid 13 sec car

about how many car lengths

drag master ???

 

What I always heard as a rule of thumb... a car length equals a 1/10 of a second give or take. Not sure if it's true or not, but I've heard it enough to make be believe it.

So I'd say a hell of a lot of car lengths though. At least 10-20

 

~20

 

thats what I thought also but some idiot in the MB forum is questioning the M3 being at least 6 car length ahead of an 04' tl in a race to about 120 mph which I think is longer than a quarter mile

he such an idiot...this is why I really hate going to that stupid forum

I told him I lost to an M3 and the 04' tl was around 6 car lengths behind the M3 and hes says

 

Well on sunday at the track I ran my buddies 95 Cobra 2x. Both times I had a 14.6 and he had 13.3's...he was approx 5-6 cars ahead of me. Thats 1.3 seconds faster so 2 seconds would prolly be like 10cars

 

the white one ??? if yes that car is sick I heard it ran a 13 flat ??

 

Yep...Gary. Even he couldn't believe he did a 13.00 that day

 

i heard 2 1/10s equal a car length so shoot with that

 

2 x 1/10 = 2/10 = 1/5s

 

Lou....Let's do 14.8 minus 13.3 equals 1.5 seconds. For simplicity I'm going to assume 100 mph although in reality at the end of the quarter the 13.3 car is going faster than that and at that instant the slower car is going 85 or 90 or whatever and is still accelerating to the finish line. At 100 mph a car is travelling 100 times 5280 ft., or 528000 ft. per hour , which is ( divided by 60 and then 60 again to get ft. per sec.) 146 ft per second. So at 100 mph the faster car is somewhere around 220 ft. ahead, or about 12 to 15 cars I guess. Others may want to check my figures but that should be about right.

 

the best is when you see a 10 second car and an 11 second car and the 10 second car has about 10 cars on the 11 second one

 

you know whats funny the guy Voodoo that does the 1/4 in 6.6 seconds...I would be just crossing the 60 ft. mark while he is half way through

 

what chuck says is an approximation assuming similar traction:

[(approx. trap mph x 5280ft x 12in / 3600sec) x (time differential)] / (car length)]

calculate that for both cars and the actual result should be somwhere inbetween.

13-14 cars.

 

thanks...so it is about 1/10 for every car length

so Ant7701 was 13 car length behind the mustang

damn that is a big difference...no wonder the M3 is such a killer

 

wait for the vid of the race...I was not 13 cars behind

 

damn lou still talkling about monday , i dont think either of us will be as fast as an m3....