Port... Any math geniouses? Cummon Sound Guys
01-17-2004, 12:46 AM
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Port... Any math geniouses? Cummon Sound Guys
Ok, I have a question that is not covered in your postings. If I have a circular port diameter, thats internal measurement is 2.5 inches... What would be the size port needed, if the port being used is square to maintain an equivilant internal volume? I can't find this info anywhere.
Thanks,
Proaudio22 where you at?
Thanks,
Proaudio22 where you at?
01-17-2004, 01:24 AM
#2
Easy enough.....
You figure out the inner circumfrance of your round port using the internal diameter with the following calculation:
Pi (3.14159) * 2.5 (your inner diameter) = 7.85" internal circumfrance
Divide that 7.85" by 4 (the 4 sides of your square port) and you get about 1.9" PER SIDE, internal diameter.
So if you cut (2) 3.4" pieces and (2) 1.9" pieces (both however long you want the port) out of 3/4" MDF, and screw together like this:
=========
= 0000000 =
= 0000000 =
=========
The top and bottom being the longer of the pieces, you'll have your port, matched the the original circular port.
Hope that helps!
You figure out the inner circumfrance of your round port using the internal diameter with the following calculation:
Pi (3.14159) * 2.5 (your inner diameter) = 7.85" internal circumfrance
Divide that 7.85" by 4 (the 4 sides of your square port) and you get about 1.9" PER SIDE, internal diameter.
So if you cut (2) 3.4" pieces and (2) 1.9" pieces (both however long you want the port) out of 3/4" MDF, and screw together like this:
=========
= 0000000 =
= 0000000 =
=========
The top and bottom being the longer of the pieces, you'll have your port, matched the the original circular port.
Hope that helps!
01-17-2004, 01:48 AM
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Originally posted by StreetEffectz
Easy enough.....
You figure out the inner circumfrance of your round port using the internal diameter with the following calculation:
Pi (3.14159) * 2.5 (your inner diameter) = 7.85" internal circumfrance
Divide that 7.85" by 4 (the 4 sides of your square port) and you get about 1.9" PER SIDE, internal diameter.
So if you cut (2) 3.4" pieces and (2) 1.9" pieces (both however long you want the port) out of 3/4" MDF, and screw together like this:
=========
= 0000000 =
= 0000000 =
=========
The top and bottom being the longer of the pieces, you'll have your port, matched the the original circular port.
Hope that helps!
Easy enough.....
You figure out the inner circumfrance of your round port using the internal diameter with the following calculation:
Pi (3.14159) * 2.5 (your inner diameter) = 7.85" internal circumfrance
Divide that 7.85" by 4 (the 4 sides of your square port) and you get about 1.9" PER SIDE, internal diameter.
So if you cut (2) 3.4" pieces and (2) 1.9" pieces (both however long you want the port) out of 3/4" MDF, and screw together like this:
=========
= 0000000 =
= 0000000 =
=========
The top and bottom being the longer of the pieces, you'll have your port, matched the the original circular port.
Hope that helps!
I think I have the jist, I'm just not sure why you'd have the width be longer that the higth?
01-17-2004, 12:29 PM
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Re: Port... Any math geniouses? Cummon Sound Guys
Originally posted by Plague
Proaudio22 where you at?
Proaudio22 where you at?
I would go about the numbers a tad differently. I would find the actual volume of the circular port, then find what size square/rectange port you actually have room for. Then based on the opening size, determine the length needed to keep an equal volume.
01-23-2004, 04:49 PM
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Well I never got a confimation of my math so I did the long version and found out the 1.9 was not the right answer, but this is...
For a circle, the area is:
Ac = pi * (D/2)^2
Ac >> area of circle
pi >> 3.14...
D >> diameter of circle
In my case, Ac = (3.14) * [(2.5 in) / 2)]^2 = 4.91 sq. in.
For a square, the area is:
As = x^2
As >> area of square
x >> length of side of a square
What you are looking for is "x", so that As = Ac. In other words,
x^2 = Ac
To find x, take the square root, so:
x = sq rt (Ac) = sq rt (4.91) = 2.21 in
So, a 2.21 x 2.21 square has the same area as a circle with diameter 2.5
For a circle, the area is:
Ac = pi * (D/2)^2
Ac >> area of circle
pi >> 3.14...
D >> diameter of circle
In my case, Ac = (3.14) * [(2.5 in) / 2)]^2 = 4.91 sq. in.
For a square, the area is:
As = x^2
As >> area of square
x >> length of side of a square
What you are looking for is "x", so that As = Ac. In other words,
x^2 = Ac
To find x, take the square root, so:
x = sq rt (Ac) = sq rt (4.91) = 2.21 in
So, a 2.21 x 2.21 square has the same area as a circle with diameter 2.5
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