got plug wires?
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#9
Originally Posted by fuzzy02CLS
How is that?
a ground wire kit creates a less resistive path to ground (ie, R is less with ground wire kit). with the same current draw (I), your voltage drop across the ground wires is V=I*R. with a smaller R due to the ground wire kit, your voltage drop decreases as well (V and R are directly related if I stays constant).
compare this to the ideal ground connection where R=0ohms which means no matter the current draw, the voltage drop is 0V.
let's play with some numbers:
assume the original ground wires give an Rold = 0.1ohm.
our current draw will stay at 10A.
so the old voltage drop Vold = 10A * 0.1ohm = 1V. This means your ground is actually at 1V instead of 0V (aka ground bounce). Therefore, the spark plug's terminals are + at 12V and - at 1V. For an actual difference of 11V.
now say our new ground wire kit gives an Rnew = 0.01ohms.
the new voltage drop Vnew = 10A * 0.01ohm = 0.1V. Your spark plug's spark is now 12V - 0.1V = 11.9V, a bigger spark!
a ground wire kit helps everything electrical in your car by keeping 0 close to 0. i may install a kit myself.
#10
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Originally Posted by gr4mm4t0n
any EEs out there that see a mistake in my logic, feel free to jump in.
a ground wire kit creates a less resistive path to ground (ie, R is less with ground wire kit). with the same current draw (I), your voltage drop across the ground wires is V=I*R. with a smaller R due to the ground wire kit, your voltage drop decreases as well (V and R are directly related if I stays constant).
compare this to the ideal ground connection where R=0ohms which means no matter the current draw, the voltage drop is 0V.
let's play with some numbers:
assume the original ground wires give an Rold = 0.1ohm.
our current draw will stay at 10A.
so the old voltage drop Vold = 10A * 0.1ohm = 1V. This means your ground is actually at 1V instead of 0V (aka ground bounce). Therefore, the spark plug's terminals are + at 12V and - at 1V. For an actual difference of 11V.
now say our new ground wire kit gives an Rnew = 0.01ohms.
the new voltage drop Vnew = 10A * 0.01ohm = 0.1V. Your spark plug's spark is now 12V - 0.1V = 11.9V, a bigger spark!
a ground wire kit helps everything electrical in your car by keeping 0 close to 0. i may install a kit myself.
a ground wire kit creates a less resistive path to ground (ie, R is less with ground wire kit). with the same current draw (I), your voltage drop across the ground wires is V=I*R. with a smaller R due to the ground wire kit, your voltage drop decreases as well (V and R are directly related if I stays constant).
compare this to the ideal ground connection where R=0ohms which means no matter the current draw, the voltage drop is 0V.
let's play with some numbers:
assume the original ground wires give an Rold = 0.1ohm.
our current draw will stay at 10A.
so the old voltage drop Vold = 10A * 0.1ohm = 1V. This means your ground is actually at 1V instead of 0V (aka ground bounce). Therefore, the spark plug's terminals are + at 12V and - at 1V. For an actual difference of 11V.
now say our new ground wire kit gives an Rnew = 0.01ohms.
the new voltage drop Vnew = 10A * 0.01ohm = 0.1V. Your spark plug's spark is now 12V - 0.1V = 11.9V, a bigger spark!
a ground wire kit helps everything electrical in your car by keeping 0 close to 0. i may install a kit myself.
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great way to explain yourself
#11
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I've been big stereo man all my life and Ive never used one before. 1) Is it true that they only come in blue and red? 2) Everyone Ive seen in a car was next to the engine, Can it be mounted where no one can see it?
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