Something to think about with subs...
#1
Something to think about with subs...
Just a little helpful note from you friendly neighborhood meddler...
You guys are sitting here deciding on different subs, or between different types and setups of the same brand (say 3 10's vs 2 12's). A quick and simple way to determine which will bump more is to find out the amount of cubic air the subs are moving. For instance:
JL 12 w7: 1.15 in. Xmax (excursion) or linear displacement, 113.04 in^2 in cone area
JL 10 w7: .9 in. Xmax (excursion) or linear displacement,
12 w7's - 1.15 x 226.08 = 259.992 in^3
10 w7's - .9 x 235.5 = 211.95 in^3
Cubic inches of displacement baby...and what you see is that the 12's beat the 10's by a solid 48.042 in^3...about 25%. That's friggin huge.
More precisely...you can calculate via effective piston area...which yields more precise results...but 2 12 w7's will end up being 33% louder than 3 10 w7's, while consuming the same power.
Just food for thought.
Austin519
You guys are sitting here deciding on different subs, or between different types and setups of the same brand (say 3 10's vs 2 12's). A quick and simple way to determine which will bump more is to find out the amount of cubic air the subs are moving. For instance:
JL 12 w7: 1.15 in. Xmax (excursion) or linear displacement, 113.04 in^2 in cone area
JL 10 w7: .9 in. Xmax (excursion) or linear displacement,
12 w7's - 1.15 x 226.08 = 259.992 in^3
10 w7's - .9 x 235.5 = 211.95 in^3
Cubic inches of displacement baby...and what you see is that the 12's beat the 10's by a solid 48.042 in^3...about 25%. That's friggin huge.
More precisely...you can calculate via effective piston area...which yields more precise results...but 2 12 w7's will end up being 33% louder than 3 10 w7's, while consuming the same power.
Just food for thought.
Austin519
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